Author Topic: hyper  (Read 1694 times)

Offline frenulem - No.5417

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hyper
« on: August 31, 2011, 03:19:28 PM »
asdsad

Offline FOOKz™

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Re: hyper
« Reply #1 on: August 31, 2011, 03:23:17 PM »
(first six look good)


I1=1.1A
I2=0.4A
I3=1.1A



(ok next problem plz...)


« Last Edit: August 31, 2011, 03:23:45 PM by FOOKz™ »

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Offline frenulem - No.5417

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Re: hyper
« Reply #2 on: August 31, 2011, 03:24:17 PM »
so i have the right idea with just adding and taking away from the junctions? TY aswell
« Last Edit: August 31, 2011, 03:25:42 PM by frenulem - No.5417 »

Offline hyper999

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Re: hyper
« Reply #3 on: August 31, 2011, 03:26:32 PM »
so i have the right idea with just adding and taking away from the junctions? TY aswell

yep.

Offline FOOKz™

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Re: hyper
« Reply #4 on: August 31, 2011, 03:32:25 PM »
[spoiler]
I1 = 1.5A
I2 = 0.3A
I3 = 0.4A
I4 = 1.5A
[/spoiler]



[spoiler]
I1 = 1A
I2 = 0.8A
I3 = 0.6A
I4 = 2.4A[/spoiler]

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Offline frenulem - No.5417

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Re: hyper
« Reply #5 on: August 31, 2011, 03:55:01 PM »
6. What value resistor would allow 2mA to flow when the pd across it is 10V? in  megohms
7.    Find the current through a 10kW resistor when the pd across it is 50mV. in  microamps

Offline FOOKz™

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Re: hyper
« Reply #6 on: August 31, 2011, 04:02:34 PM »
6. What value resistor would allow 2mA to flow when the pd across it is 10V? in  megohms
7.    Find the current through a 10kW resistor when the pd across it is 50mV. in  microamps

R = V / I
R = 10 / 0.002
R = 5,000 ohms
R = 0.005M ohms

I = P / V
I = 10,000 / 0.05
I = 200,000 amps
I = 200,000,000,000 micro amps

^^ seriously what the F###

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Offline frenulem - No.5417

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Re: hyper
« Reply #7 on: August 31, 2011, 04:05:35 PM »
got em wrong fookz
« Last Edit: August 31, 2011, 04:07:49 PM by frenulem - No.5417 »

Offline hyper999

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Re: hyper
« Reply #8 on: August 31, 2011, 04:49:23 PM »
on the first one

v1 = 18

really fren? really!?

should be 6

Offline FOOKz™

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Re: hyper
« Reply #9 on: August 31, 2011, 05:00:47 PM »
6. What value resistor would allow 2mA to flow when the pd across it is 10V? in  megohms
7.    Find the current through a 10kW resistor when the pd across it is 50mV. in  microamps


R = V / I
R = 10 / 0.002
R = 5,000 ohms
R = 0.005M ohms

I = P / V
I = 10,000 / 0.05
I = 200,000 amps
I = 200,000,000,000 micro amps

^^ seriously what the F###



last time i checked it was I = P / V and R = V / I. whatever lol





facepalm:
circuit1:
[spoiler]V1 = 6V
V2 = 6V
V3 = 6V[/spoiler]

circuit2:
[spoiler]V1 = 2V[/spoiler]

circuit3:
[spoiler]V1 = 6v
V2 = 0.6v
V3 = 11.4v
V4 = I need to brush up on Nodal Voltage Analysis, Mesh Current Analysis, and Thevenins Theorem LOL[/spoiler]



« Last Edit: August 31, 2011, 05:02:42 PM by FOOKz™ »

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